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Heat transfer in an axial symmetric fin
Posted 23 apr 2017, 18:07 GMT-4 Heat Transfer & Phase Change, Results & Visualization, Studies & Solvers Version 5.2, Version 5.2a 2 Replies
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Hi guys,
I am trying to find the heat transfer from an axially symmetric fin using COMSOL. What I've done is to create a fin using the axisymmetric mode. This essentially looks like a 2D rectangle on the screen. To calculate the heat tranfered I've then selected the appropriate sides in a Line Integral and found ht.ntflux. Is this the heat transfered for the whole fin? I've got a slight feeling that I might need to times it by 2 * pi * r however I'm not sure what the 'r' value is in axisymmetric mode, if I perform a line integral on 'r' it gives the unit at m^2. Could anyone offer any help?
Thanks very much
I am trying to find the heat transfer from an axially symmetric fin using COMSOL. What I've done is to create a fin using the axisymmetric mode. This essentially looks like a 2D rectangle on the screen. To calculate the heat tranfered I've then selected the appropriate sides in a Line Integral and found ht.ntflux. Is this the heat transfered for the whole fin? I've got a slight feeling that I might need to times it by 2 * pi * r however I'm not sure what the 'r' value is in axisymmetric mode, if I perform a line integral on 'r' it gives the unit at m^2. Could anyone offer any help?
Thanks very much
2 Replies Last Post 27 apr 2017, 02:06 GMT-4
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Posted:
8 years ago
George,
I'm not sure if I could imagine your geometry correctly. However, in this case, I'd simply change the expression inside the integral to "1" and see if it calculates the correct surface area.
Amin,
I'm not sure if I could imagine your geometry correctly. However, in this case, I'd simply change the expression inside the integral to "1" and see if it calculates the correct surface area.
Amin,
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Posted:
8 years ago
If you tick the box "calculate surface integral" you get the integral over the cylinder, otherwise you get only the line integral.
L
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