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How to create a function whose output is either 1 or -1?
Posted 25 mag 2017, 11:59 GMT-4 Materials, Parameters, Variables, & Functions 2 Replies
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Hello everyone,
I would like to create a function that only gives the result of either 1 or -1.
But the probability for these two different results depends on a time-varying variable defined in COMSOL.
For example, at t0, the probability for 1 is 70%, and at t1, it might decrease to 54%, and so on.
Does anyone know how to do this in COMSOL?
I would like to create a function that only gives the result of either 1 or -1.
But the probability for these two different results depends on a time-varying variable defined in COMSOL.
For example, at t0, the probability for 1 is 70%, and at t1, it might decrease to 54%, and so on.
Does anyone know how to do this in COMSOL?
2 Replies Last Post 25 mag 2017, 22:18 GMT-4
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Posted:
8 years ago
Updated:
8 years ago
Hi
One way is to express it in form of a conditional statement. In the variable section, you may define your function, F, as:
F= if ( probability > 0.7 , 1 , -1 )
It returns F=1 if probability > 0.7, and F=-1 otherwise.
Amin
One way is to express it in form of a conditional statement. In the variable section, you may define your function, F, as:
F= if ( probability > 0.7 , 1 , -1 )
It returns F=1 if probability > 0.7, and F=-1 otherwise.
Amin
Please login with a confirmed email address before reporting spam
Posted:
8 years ago
Updated:
8 years ago
Hi, Mohammad Amin,
Thanks for your reply. But I'm afraid I didn't express myself clearly.
The function is actually used to randomly produce the result of 1 or -1.
But the probability for 1 or -1 are not the same.
For instance, if the probability for 1 is 70%, it means 70 out of 100 times when you run the function, you will get 1.
One way I think that might work is to combine "if" and "random" functions.
Let's say, if the random function is uniform distribution with mean and range of 0 and 1, respectively, which means the output ranges from -0.5 to 0.5.
Also, assume the probability for 1 is 70%, then the function should be "if(random(t)<=-0.2, -1, 1)".
I will run some tests to see if it works.
Thanks for your reply. But I'm afraid I didn't express myself clearly.
The function is actually used to randomly produce the result of 1 or -1.
But the probability for 1 or -1 are not the same.
For instance, if the probability for 1 is 70%, it means 70 out of 100 times when you run the function, you will get 1.
One way I think that might work is to combine "if" and "random" functions.
Let's say, if the random function is uniform distribution with mean and range of 0 and 1, respectively, which means the output ranges from -0.5 to 0.5.
Also, assume the probability for 1 is 70%, then the function should be "if(random(t)<=-0.2, -1, 1)".
I will run some tests to see if it works.