Henrik Sönnerlind
COMSOL Employee
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Posted:
6 years ago
23 nov 2018, 01:59 GMT-5
Hi,
Lambda is described in the user's guide as:
"This law requires one more material parameter lambda, describing the width of the “plastic” region. The Shape factor lambda is the ratio between the plastic (constant stress) part of Gic and the total “inelastic” part of Gic."
Looking at the figure just above that text (in the section 'Multilinear Separation Law' in the theory chapter) will make things clear.
As for the penalty factor unit, an ordinary spring has a stiffness with unit N/m. If that is distributed over an area, you divide by m^2.
Regards,
Henrik
-------------------
Henrik Sönnerlind
COMSOL
Hi,
Lambda is described in the user's guide as:
"This law requires one more material parameter *lambda*, describing the width of the “plastic” region. The Shape factor *lambda* is the ratio between the plastic (constant stress) part of Gic and the total “inelastic” part of Gic."
Looking at the figure just above that text (in the section 'Multilinear Separation Law' in the theory chapter) will make things clear.
As for the penalty factor unit, an ordinary spring has a stiffness with unit N/m. If that is distributed over an area, you divide by m^2.
Regards,
Henrik
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Posted:
6 years ago
24 nov 2018, 11:16 GMT-5
Hello Henrik,
Thank you so much for the explaination.
I have a follow-up question for you. The multi-linear decohesive law uses both ERR (J/m^2) & interficial strength (Pa) together as the criterion for separation. I'm wondering how can I use interfial strength only as the criterion, meaning, separation occur right after shear stress exceeds interficial shear strength.
Thank you!
Best,
Xiaokang
Hello Henrik,
Thank you so much for the explaination.
I have a follow-up question for you. The multi-linear decohesive law uses both ERR (J/m^2) & interficial strength (Pa) together as the criterion for separation. I'm wondering how can I **use interfial strength only** as the criterion, meaning, separation occur right after shear stress exceeds interficial shear strength.
Thank you!
Best,
Xiaokang
Henrik Sönnerlind
COMSOL Employee
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Posted:
6 years ago
26 nov 2018, 04:50 GMT-5
Updated:
6 years ago
26 nov 2018, 15:31 GMT-5
Hi Xiaokang,
The problem with using a material law in which the layer breaks instantaneously at a certain peak stress is that it may be difficult to obtain convergence in such a model.
But if you want to try it, you can just use the linear separation law, and set GIc such that it matches the energy in the layer exactly at peak stress, that is 0.5*max_stress^2/penalty_factor. Probably that value should be multiplied by a small number, like 1.001 or so to avoid division by zero.
Regards,
Henrik
-------------------
Henrik Sönnerlind
COMSOL
Hi Xiaokang,
The problem with using a material law in which the layer breaks instantaneously at a certain peak stress is that it may be difficult to obtain convergence in such a model.
But if you want to try it, you can just use the linear separation law, and set GIc such that it matches the energy in the layer exactly at peak stress, that is 0.5\*max\_stress^2/penalty\_factor. Probably that value should be multiplied by a small number, like 1.001 or so to avoid division by zero.
Regards,
Henrik