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Posted:
1 decade ago
27 mar 2012, 17:36 GMT-4
emw.Ex is the total field. Scattered field is (emw.Ex-emw.Ebx)
emw.Ex is the total field. Scattered field is (emw.Ex-emw.Ebx)
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Posted:
1 decade ago
27 mar 2012, 17:42 GMT-4
So to normalize to see enhancement, I would need:
(emw.Ex-emw.Ebx)/(emw.Ebx)
Based on your response is this the correct formulation
So to normalize to see enhancement, I would need:
(emw.Ex-emw.Ebx)/(emw.Ebx)
Based on your response is this the correct formulation
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Posted:
1 decade ago
27 mar 2012, 18:06 GMT-4
It depends what you mean by "enhancement" :)
In my case, I use the following quantity integral(abs(Escattered)^2)/integral(abs(Ebackground)^2).
It depends what you mean by "enhancement" :)
In my case, I use the following quantity integral(abs(Escattered)^2)/integral(abs(Ebackground)^2).
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Posted:
1 decade ago
27 mar 2012, 18:26 GMT-4
Well I can clarify. I am dealing with an electric field being incident into a metal nanoantenna cavity from a substrate. So there is amplification of the electric field due to local surface plasmons, which increases the amplitude of my electric field in the cavity. I am trying to normalized the scattered field by the background incident field to get a sense of this quantity.
This is something like (|Ecav|/|Esig|)^2 which I believe is an enhancement factor.
So I was assuming Ecav/Esig was something like emw.Ex/emw.Ebx.
I am to give your expression a try.
In your expression is Escattered= (emw.Ex-emw.Ebx)
and Ebackground = emw.Ebx
I am not sure how to do the integration on my 2-D surface plot but that is a separate issue.
Well I can clarify. I am dealing with an electric field being incident into a metal nanoantenna cavity from a substrate. So there is amplification of the electric field due to local surface plasmons, which increases the amplitude of my electric field in the cavity. I am trying to normalized the scattered field by the background incident field to get a sense of this quantity.
This is something like (|Ecav|/|Esig|)^2 which I believe is an enhancement factor.
So I was assuming Ecav/Esig was something like emw.Ex/emw.Ebx.
I am to give your expression a try.
In your expression is Escattered= (emw.Ex-emw.Ebx)
and Ebackground = emw.Ebx
I am not sure how to do the integration on my 2-D surface plot but that is a separate issue.
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Posted:
1 decade ago
27 mar 2012, 20:46 GMT-4
I am not sure how to do the integration on my 2-D surface plot but that is a separate issue.
That's an easy part. Define integration operator on your domain (Definition-Model Couplings-Integration). Then in post-processing use intop1(abs(field)) to get the value of integral.
This way you can define amplification inside the entire cavity. I don't think the amplification at particular points of the cavity has much meaning.
[QUOTE]
I am not sure how to do the integration on my 2-D surface plot but that is a separate issue.
[/QUOTE]
That's an easy part. Define integration operator on your domain (Definition-Model Couplings-Integration). Then in post-processing use intop1(abs(field)) to get the value of integral.
This way you can define amplification inside the entire cavity. I don't think the amplification at particular points of the cavity has much meaning.
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Posted:
1 decade ago
16 mag 2013, 13:50 GMT-4
Could someone clarify how to specify the face where the background electric field is incident on the system?
I have an air block with spherical scatterers embedded in it. The background E field needs to be incident on one of the faces of the cube, and I need to study the fields within the block. I am using scattering boundary condition for all the faces of the block.
Could someone clarify how to specify the face where the background electric field is incident on the system?
I have an air block with spherical scatterers embedded in it. The background E field needs to be incident on one of the faces of the cube, and I need to study the fields within the block. I am using scattering boundary condition for all the faces of the block.
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Posted:
1 decade ago
21 lug 2013, 21:42 GMT-4
The same question.
Thanks in advance.
The same question.
Thanks in advance.