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Simple Linear Thermal Expansion Theory vs Model

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I'm modelling thermal expansion in a 2D beam with 10mm width (L0) and 0.1 mm height. The volume reference temperature is 25 degC and the beam is at uniform temperature of 45 degC for a dT of 20 degC. The thermal expansion coefficient is 23e-6 1/K (alpha).

From a simple 1D thermal expansion calculation: dL/L0 = alpha x dT = 23e-6 1/degC x 20 degC = 4.60e-4 also, dL = alpha x dT x L0 = 23e-6 1/degC x 20 degC x 0.01 m = 4.60e-6 m

However, in my model, I get dL/L0 = 5.75e-4 (first principle strain) and dL = 5.75e-6 m (displacement).

Can anyone please help me understand the discrepancy between the theoretical calculation and the COMSOL model? I've attached my model file.



1 Reply Last Post 3 feb 2022, 13:49 GMT-5
Jeff Hiller COMSOL Employee

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Posted: 2 years ago 3 feb 2022, 13:49 GMT-5

Hello Sibi,

You set up the model as plane strain. To approximate a beam, you would need to make it plane stress. When you do that, the model returns the displacement you expected.

Best regards,

Jeff

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Jeff Hiller
Hello Sibi, You set up the model as plane strain. To approximate a beam, you would need to make it plane stress. When you do that, the model returns the displacement you expected. Best regards, Jeff

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