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volume within a closed isosurface

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Hello

WIthin a 3D domain containing closed isosurfaces, is there a way to calculate the volume of material contained within each isosurface?

Many thanks

Dan

3 Replies Last Post 7 dic 2012, 02:58 GMT-5
Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)

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Posted: 1 decade ago 5 dic 2012, 01:18 GMT-5
Hi

if you define an integration over a domain, and use the Bolean operand "(My_Var < My_value)" I would expect to get the total volume of the region obeying the Bolean condition, no ?

In COMSOL a 3D integration is by default: integrate_over_my_selections_of_Domains(argument*dx*dy*dz)
while the dx*dy*dz is "implicit" (or it might be 2*pi*r*rd*dz in 2D axi)
--
Good luck
Ivar
Hi if you define an integration over a domain, and use the Bolean operand "(My_Var < My_value)" I would expect to get the total volume of the region obeying the Bolean condition, no ? In COMSOL a 3D integration is by default: integrate_over_my_selections_of_Domains(argument*dx*dy*dz) while the dx*dy*dz is "implicit" (or it might be 2*pi*r*rd*dz in 2D axi) -- Good luck Ivar

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Posted: 1 decade ago 7 dic 2012, 01:25 GMT-5
HI Ivar

Thanks I hadn't thought of using a boolean expression.

Works perfectly of course

Thanks again

Dan
HI Ivar Thanks I hadn't thought of using a boolean expression. Works perfectly of course Thanks again Dan

Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)

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Posted: 1 decade ago 7 dic 2012, 02:58 GMT-5
Hi

one warning, do not use Boolean on average operators, as the normalisation is not taking into account the boolean expression and you get too low values. Then its worth to write out the two integration fully, both with the same boolean expression in the numerator and de-numerator of the average expression

--
Good luck
Ivar
Hi one warning, do not use Boolean on average operators, as the normalisation is not taking into account the boolean expression and you get too low values. Then its worth to write out the two integration fully, both with the same boolean expression in the numerator and de-numerator of the average expression -- Good luck Ivar

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