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How to rotate a 2D Plot?

Posted 5 feb 2013, 11:16 GMT-5 Results & Visualization Version 5.2, Version 5.2a 4 Replies

Kenji Reichling
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I built a model with a 3D geometry. Unfortunately the created 2D plot (postprocessing), which is based on a cut plane, is rotated by 90°. Is it possible to rotate the 2D plot back by 90° or to exchange the axis (x/y -> y/x)?

Thank you in advance!
4 Replies Last Post 5 set 2016, 03:50 GMT-4
Josh Thomas Certified Consultant
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Posted: 1 decade ago 5 feb 2013, 12:17 GMT-5
Kenji-

When you define your Cut Plane you can define a yx-plane instead of an xy-plane. This should work for you.

Regards,
Josh Thomas
AltaSim Technologies
Kenji- When you define your Cut Plane you can define a yx-plane instead of an xy-plane. This should work for you. Regards, Josh Thomas AltaSim Technologies
Kenji Reichling
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Posted: 1 decade ago 5 feb 2013, 12:33 GMT-5
Great! That works for me.

Thank you very much!
Great! That works for me. Thank you very much!
Magnus Hedlund
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Posted: 8 years ago 5 set 2016, 03:44 GMT-4
Hi!

I'm at loss for how to do this with a general plane type (which I have to use since the plane I want to plot has it's normal pointing towards x^-y^).

Thanks in advance for answer!

BR
Magnus
Hi! I'm at loss for how to do this with a general plane type (which I have to use since the plane I want to plot has it's normal pointing towards x^-y^). Thanks in advance for answer! BR Magnus
Magnus Hedlund
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Posted: 8 years ago 5 set 2016, 03:50 GMT-4
I made a quick breakthrough just after posting :)

A parameterized surface did the trick.

BR
Magnus

xkcd.com/979/


Hi!

I'm at loss for how to do this with a general plane type (which I have to use since the plane I want to plot has it's normal pointing towards x^-y^).

Thanks in advance for answer!

BR
Magnus

I made a quick breakthrough just after posting :) A parameterized surface did the trick. BR Magnus https://xkcd.com/979/ [QUOTE] Hi! I'm at loss for how to do this with a general plane type (which I have to use since the plane I want to plot has it's normal pointing towards x^-y^). Thanks in advance for answer! BR Magnus [/QUOTE]

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