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Calculating % volume of 3D domain encompassed by a surface
Posted 21 nov 2013, 09:14 GMT-5 Geometry, Results & Visualization, Structural Mechanics Version 4.0a 1 Reply
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I am running version 4.0a.
I have a system with transient diffusion of dilute species (implemented via the 'transport in dilute species' physics) throughout a cylindrical domain. To visualise my results at a given time t, I have made a 3D plot group and applied a filter for concentration of one of my species (lactate, denoted LAC) with the following expression:
1*(LAC<=0.05)
This gives me results as expected, i.e. a surface plot of regions within my domain where the concentration is less than or equal to 0.05 mol/m3
I now want to know the percentage of my overall domain which is contained within this surface plot. In other words:
"what percentage of my domain volume has a concentration of LAC<=0.05mol/m3?"
I know the volume occupied by my entire domain, so is there a way of evaluating the volume 'encompassed' by the surface? If I can evaluate this quantity through time, then that would be ideal.
Hope my query is clear, and thank you in advance for your help,
Karan
I have a system with transient diffusion of dilute species (implemented via the 'transport in dilute species' physics) throughout a cylindrical domain. To visualise my results at a given time t, I have made a 3D plot group and applied a filter for concentration of one of my species (lactate, denoted LAC) with the following expression:
1*(LAC<=0.05)
This gives me results as expected, i.e. a surface plot of regions within my domain where the concentration is less than or equal to 0.05 mol/m3
I now want to know the percentage of my overall domain which is contained within this surface plot. In other words:
"what percentage of my domain volume has a concentration of LAC<=0.05mol/m3?"
I know the volume occupied by my entire domain, so is there a way of evaluating the volume 'encompassed' by the surface? If I can evaluate this quantity through time, then that would be ideal.
Hope my query is clear, and thank you in advance for your help,
Karan
1 Reply Last Post 22 nov 2013, 02:28 GMT-5