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Posted:
8 years ago
21 giu 2016, 16:05 GMT-4
That photo is fantastic! Impressive.
However, I think a primary issue with simulating it is symmetry. It appears the structure is symmetric, yet the deformation is not. Something needs to break the symmetry: the equations won't do so on their own. This may not be your issue but it's the most noticeable thing I see.
That photo is fantastic! Impressive.
However, I think a primary issue with simulating it is symmetry. It appears the structure is symmetric, yet the deformation is not. Something needs to break the symmetry: the equations won't do so on their own. This may not be your issue but it's the most noticeable thing I see.
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Posted:
8 years ago
21 giu 2016, 16:12 GMT-4
Daniel,
Thank you for your input. I'll start trying to take a look at the equations and symmetry.
Daniel,
Thank you for your input. I'll start trying to take a look at the equations and symmetry.
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Posted:
8 years ago
28 giu 2016, 16:51 GMT-4
I still can't seem to get any out of plane motion without adding in a small z-direction force. And when I do add the force, the entire geometry acts as if it is a solid member. If anyone would be able to expand on how to work with equations/symmetry or help further I would appreciate it.
I still can't seem to get any out of plane motion without adding in a small z-direction force. And when I do add the force, the entire geometry acts as if it is a solid member. If anyone would be able to expand on how to work with equations/symmetry or help further I would appreciate it.
Henrik Sönnerlind
COMSOL Employee
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Posted:
8 years ago
29 giu 2016, 09:47 GMT-4
Hi,
This is a rather difficult analysis, but here are some hints:
1. The most important is that the problem is strongly geometrically nonlinear. So you must activate geometric nonlinearity in the settings for the study step.
2. I would recommend a loading by a prescribed displacement, which is more stable.
3. The load must be applied gradually using an auxiliary sweep.
4. Solving a buckling problem is a numerically very sensitive problem. Please study this example, which deals with how to pass the instability and get into the post-buckling state.
www.comsol.com/model/postbuckling-analysis-of-a-hinged-cylindrical-shell-10257
Along these lines of that example, I think that using sqrt(w^2) as the controlling parameter could be a good idea.
5. You can read more about buckling in general in this blog post:
www.comsol.com/blogs/buckling-structures-suddenly-collapse/
Regards,
Henrik
Hi,
This is a rather difficult analysis, but here are some hints:
1. The most important is that the problem is strongly geometrically nonlinear. So you must activate geometric nonlinearity in the settings for the study step.
2. I would recommend a loading by a prescribed displacement, which is more stable.
3. The load must be applied gradually using an auxiliary sweep.
4. Solving a buckling problem is a numerically very sensitive problem. Please study this example, which deals with how to pass the instability and get into the post-buckling state.
https://www.comsol.com/model/postbuckling-analysis-of-a-hinged-cylindrical-shell-10257
Along these lines of that example, I think that using sqrt(w^2) as the controlling parameter could be a good idea.
5. You can read more about buckling in general in this blog post:
https://www.comsol.com/blogs/buckling-structures-suddenly-collapse/
Regards,
Henrik
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Posted:
8 years ago
5 lug 2016, 10:45 GMT-4
Hello Henrik,
Thank you for the guidance and the links to the tutorials for help. I'm still learning as I go and I'm a little confused by what you mean using sqrt(w^2) as the controlling parameter. Does that mean use it as the stop condition within the solver?
Thank you,
Thomas
Hello Henrik,
Thank you for the guidance and the links to the tutorials for help. I'm still learning as I go and I'm a little confused by what you mean using sqrt(w^2) as the controlling parameter. Does that mean use it as the stop condition within the solver?
Thank you,
Thomas
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Posted:
8 years ago
5 lug 2016, 14:23 GMT-4
Never mind, I found what was meant by the controlling parameter. Thank you again.
Never mind, I found what was meant by the controlling parameter. Thank you again.