Menu

Discussion Forum

New Discussion
Filtra

Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.

Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.

Cut Plane 3d not through whole geometry

Posted 7 giu 2016, 08:22 GMT-4 Geometry, Results & Visualization Version 4.4 4 Replies

Alexander Rave
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Hello,

I am simulating a fluid flow with heat transfer in a bent rectangular microchannel. For postprocessing, I defined several cut planes where I do integrations on (derived values). It all worked well as long as I had only one arc. Now I combined two identical arcs. Unfortunately, some of the cut planes cut two or three times through my channel, making it impossible to do evaluations on it (see attached picture ). So here are my questions:

Is there a way to tell COMSOL to stop cutting through the geometry at a certain (for example) x-value?

Or is it possible to do the surface integration only on a part of the whole cut plane?

I am looking forward for some ideas.

Kind regards,
Alexander

Attachments:

4 Replies Last Post 7 giu 2016, 09:43 GMT-4
Jeff Hiller COMSOL Employee

Please login with a confirmed email address before reporting spam

Posted: 8 years ago 7 giu 2016, 08:52 GMT-4
Hello Alexander,
Cut Planes are planes in the mathematical sense, hence infinite.
The trick is to include a boolean in the expression your integrand.
Say you want to intergrate "u" in the part of the cur plane that has coordinates x>15e-3 (i.e. the rightmost of the three intersections between your geometry and the cut plane in your screenshot) the you can ask COMSOL to integrate "u*((x>15e-3)".
Best,
Jeff
Hello Alexander, Cut Planes are planes in the mathematical sense, hence infinite. The trick is to include a boolean in the expression your integrand. Say you want to intergrate "u" in the part of the cur plane that has coordinates x>15e-3 (i.e. the rightmost of the three intersections between your geometry and the cut plane in your screenshot) the you can ask COMSOL to integrate "u*((x>15e-3)". Best, Jeff
Alexander Rave
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Posted: 8 years ago 7 giu 2016, 09:19 GMT-4
Hello Jeff,

thank your very much for your quick response. It seems that this works.

I have one further question: When I am doing not an integration, but an averaging, will I get the right result? Because when COMSOL takes just the integrand as zero, but continues to integrate over the full cut plane, than I will get the wrong average value because the surface is to large.

But if COMSOL does not sum up the surface elements where the boolean value is false, then this should work, too.

Best wishes from Hamburg, Germany,
Alexander

Hello Jeff, thank your very much for your quick response. It seems that this works. I have one further question: When I am doing not an integration, but an averaging, will I get the right result? Because when COMSOL takes just the integrand as zero, but continues to integrate over the full cut plane, than I will get the wrong average value because the surface is to large. But if COMSOL does not sum up the surface elements where the boolean value is false, then this should work, too. Best wishes from Hamburg, Germany, Alexander
Jeff Hiller COMSOL Employee

Please login with a confirmed email address before reporting spam

Posted: 8 years ago 7 giu 2016, 09:24 GMT-4
You can use the boolean trick above also to compute the surface area of the rightmost cross-section: integrate "x>15e-3". Then you get the average by dividing the integral of "u*(x>15e-3)" by the integral of "x>15e-3" .
Jeff
You can use the boolean trick above also to compute the surface area of the rightmost cross-section: integrate "x>15e-3". Then you get the average by dividing the integral of "u*(x>15e-3)" by the integral of "x>15e-3" . Jeff
Alexander Rave
Send Private Message Flag post as spam

Please login with a confirmed email address before reporting spam

Posted: 8 years ago 7 giu 2016, 09:43 GMT-4
Thank you again.

Yes, I have to do it as your suggested. Just applying the averaging function with the "boolean trick" yields the wrong value because obviously Comsol devides the right integrated value by the total and not the "boolean" surface.

That's everything I wanted to find out :-)

Kind regards,
Alexander
Thank you again. Yes, I have to do it as your suggested. Just applying the averaging function with the "boolean trick" yields the wrong value because obviously Comsol devides the right integrated value by the total and not the "boolean" surface. That's everything I wanted to find out :-) Kind regards, Alexander

Note that while COMSOL employees may participate in the discussion forum, COMSOL® software users who are on-subscription should submit their questions via the Support Center for a more comprehensive response from the Technical Support team.

Suggested Content