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What does the Kx-Hy mean?

Posted 11 gen 2021, 09:40 GMT-5 1 Reply

Hu Guanghan
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Hi there,

I am confused about the Jz=Kx-Hy in comsol, what does it mean? Kx-Hy, I do not know the meaning. Please help me solve the problem. !!

1 Reply Last Post 11 gen 2021, 14:20 GMT-5
Robert Koslover Certified Consultant
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Posted: 4 years ago 11 gen 2021, 14:20 GMT-5

You didn't mention the context or module or type of problem for your question, but I'll take a guess that it is one in the overall electromagnetic family. I'm also guessing that you are in a frequency domain context, because if field quantities are proportional to exp(i k r) then the curl (dell cross) operation "brings down" the k vector, so to speak, and there might be a k involved. I'm also guessing that you are using the AC/DC module. Given that Ampere's law says that the Curl of H = current density (if we ignore the Maxwell displacement current term), then one can see how this could work out to something a bit similar to what you wrote -- but it wouldn't have a minus sign in the expression, but rather multiplication. And there would likely be other terms too, but perhaps those are not included in your particular model for reasons unknown to me. Anyway, I encourage you to tell the Forum more about what you are actually trying to compute, what module you are using, and... maybe you could even post your model to the Forum, if you want more specific and useful advice? Good luck.

-------------------
Scientific Applications & Research Associates (SARA) Inc.
www.comsol.com/partners-consultants/certified-consultants/sara
You didn't mention the *context* or *module* or *type of problem* for your question, but I'll take a guess that it is one in the overall electromagnetic family. I'm also guessing that you are in a frequency domain context, because if field quantities are proportional to exp(i k r) then the curl (dell cross) operation "brings down" the k vector, so to speak, and there might be a k involved. I'm also guessing that you are using the AC/DC module. Given that Ampere's law says that the Curl of H = current density (if we ignore the Maxwell displacement current term), then one can see how this could work out to something a bit similar to what you wrote -- but it wouldn't have a minus sign in the expression, but rather multiplication. And there would likely be other terms too, but perhaps those are not included in your particular model for reasons unknown to me. Anyway, I encourage you to tell the Forum more about what you are actually trying to compute, what module you are using, and... maybe you could even post your model to the Forum, if you want more specific and useful advice? Good luck.

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