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Caculate the area of a range of voltage
Posted 18 giu 2014, 05:29 GMT-4 Low-Frequency Electromagnetics Version 4.4 2 Replies
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Hello to all,
I'm actually modeling a model of a simple electrode. The electrode is a cylinder of Platinum and I apply 1V on it, the current is passing through a muscle, and collected by a ground.
After the calculation, I create a cut plane 2D to see the behavior of the Voltage/Current density/Electic Field, inside the muscle.
My question is : Is it possible to calculate the area surface (on my cut plane) of a range of Voltage or Current density or Electic Field ?
For instance, on the picture "Voltage Cut plane", we can observe the voltage on my cut plane (range 0 V to 0.68V). What I want to calculate is the area (in m²) of the geometric surface where the range is 0.25V to 0.68V (see picture 2). Is there a function to do that in COMSOL software? I don't see how to do that..
Someone can help me to find the solution?
Thank you.
Antoine.
I'm actually modeling a model of a simple electrode. The electrode is a cylinder of Platinum and I apply 1V on it, the current is passing through a muscle, and collected by a ground.
After the calculation, I create a cut plane 2D to see the behavior of the Voltage/Current density/Electic Field, inside the muscle.
My question is : Is it possible to calculate the area surface (on my cut plane) of a range of Voltage or Current density or Electic Field ?
For instance, on the picture "Voltage Cut plane", we can observe the voltage on my cut plane (range 0 V to 0.68V). What I want to calculate is the area (in m²) of the geometric surface where the range is 0.25V to 0.68V (see picture 2). Is there a function to do that in COMSOL software? I don't see how to do that..
Someone can help me to find the solution?
Thank you.
Antoine.
2 Replies Last Post 18 giu 2014, 09:02 GMT-4
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Posted:
1 decade ago
Maybe you can put a surface integral node in the results -> derived values node, and use as the expression something like
if(V>0.25&&V<0.68,1,0)
if(V>0.25&&V<0.68,1,0)
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Posted:
1 decade ago
And you were right!
Thank you Pieter for you quick answer!
Thank you Pieter for you quick answer!