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temperature is a linear function of the length of the geometry

Posted 25 mar 2015, 15:53 GMT-4 Heat Transfer & Phase Change 4 Replies

Om Singh
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hi,
i am simulating heat transfer in a cubic solar cavity with one face opening to the ambient. i want to give temperature boundary condition on a phase adjacent to the aperture as a linear function of the length of the surface.
i mean the temperature changes linearly on a phase from going one end to another.
anybody help me !

thanks in adv !
4 Replies Last Post 28 mar 2015, 20:16 GMT-4
Lasse Murtomäki
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Posted: 10 years ago 26 mar 2015, 02:02 GMT-4
Define a function (piecewise/analytic) representing your temperature profile, and give that as the boundary condition on the selected boundary.

br
Lasse
Define a function (piecewise/analytic) representing your temperature profile, and give that as the boundary condition on the selected boundary. br Lasse
Om Singh
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Posted: 10 years ago 28 mar 2015, 01:11 GMT-4
thanks for helpful advice.
one more doubt, can i choose the temperature as a function of co-ordinate in that particular direction if yes then how. bcz i failed to do so.

thanks for helpful advice. one more doubt, can i choose the temperature as a function of co-ordinate in that particular direction if yes then how. bcz i failed to do so.
Lasse Murtomäki
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Posted: 10 years ago 28 mar 2015, 07:23 GMT-4
Let's say that you have a surface in the xy plane on which you want to set a linear temperature profile as a function of x. Write for example

293.15 [K]+(x/0.5)[K/m]

in in Temperature definition box (T0). x is in meters, hence this simple equation creates a linear profile.

br
Lasse
Let's say that you have a surface in the xy plane on which you want to set a linear temperature profile as a function of x. Write for example 293.15 [K]+(x/0.5)[K/m] in in Temperature definition box (T0). x is in meters, hence this simple equation creates a linear profile. br Lasse
Om Singh
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Posted: 10 years ago 28 mar 2015, 20:16 GMT-4
its working now !

thanks again !

rg
Om Singh
its working now ! thanks again ! rg Om Singh

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